Question:
Find the equation of a line
whose slope is - 3 and which passes through the point ( - 2, 3);
Solution:
As slope is given $m=-3$ and line is passing through point $(-2,3) .$ Using
slope - intercept form of equation of line, we will find intercept first
$y=m x+c$ ................(1)
$3=-3(-2)+c$
$3=6+c$
$c=3-6$
$c=-3$
Putting the value of c in equation (1), we have
$y=-3 x+(-3)$
$y=-3 x-3$
$3 x+y+3=0$
So, the required equation of line is 3x + y + 3 = 0.