Question:
Find the equation of a circle with Centre $(-3,-2)$ and radius 6
Solution:
The general form of the equation of a circle is:
$(x-h)^{2}+(y-k)^{2}=r^{2}$
Where, (h, k) is the centre of the circle.
r is the radius of the circle.
Substituting the centre and radius of the circle in he general form:
$\Rightarrow(x-(-3))^{2}+(y-(-2))^{2}=6^{2}$
$\Rightarrow(x+3)^{2}+(y+2)^{2}=36$
Ans; equation of a circle with Centre $(-3,-2)$ and radius 6 is:
$\Rightarrow(x+3)^{2}+(y+2)^{2}=36$
