Find the cubes of the following numbers:

Question:

Find theĀ  cubes of the following numbers:

(i) 7

(ii) 12

(iii) 16

(iv) 21

(v) 40

(vi) 55

(vii) 100

(viii) 302

(ix) 301

Solution:

Cube of a number is given by the number raised to the power three.

(i) Cube of $7=7^{3}=7 \times 7 \times 7=343$

(ii) Cube of $12=12^{3}=12 \times 12 \times 12=1728$

(iii) Cube of $16=16^{3}=16 \times 16 \times 16=4096$

(iv) Cube of $21=21^{3}=21 \times 21 \times 21=9261$

(v) Cube of $40=40^{3}=40 \times 40 \times 40=64000$

(vi) Cube of $55=55^{3}=55 \times 55 \times 55=166375$

(vii) Cube of $100=100^{3}=100 \times 100 \times 100=1000000$

(viii) Cube of $302=302^{3}=302 \times 302 \times 302=27543608$

(ix) Cube of $301=301^{3}=301 \times 301 \times 301=27270901$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now