Question:
Find the cubes of:
(i) −11
(ii) −12
(iii) −21
Solution:
(i)
Cube of $-11$ is given as:
$(-11)^{3}=-11 \times-11 \times-11=-1331$
Thus, the cube of 11 is $(-1331)$.
(ii)
Cube of $-12$ is given as:
$(-12)^{3}=-12 \times-12 \times-12=-1728$
Thus, the cube of $-12$ is $(-1728)$.
(iii)
Cube of $-21$ is aiven as:
$(-21)^{3}=-21 \times-21 \times-21=-9261$
Thus, the cube of $-21$ is $(-9261)$.