Question:
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Solution:
Given:
Lengths of the parallel sides are $15 \mathrm{~cm}$ and $9 \mathrm{~cm}$.
Height $=8 \mathrm{~cm}$
Area of trapezium $=\frac{1}{2} \times($ Sum of the opposite sides $) \times($ Distance between the parallel sides $)$
$=\frac{1}{2} \times(15+9) \times(8)$
$=96 \mathrm{~cm}^{2}$