Find the area of the shaded field shown in figure.

In a figure, join ED

From fiqure, radius of semi-circle $D F E, r=6-4=2 \mathrm{~m}$

Now, $\quad$ area of rectangle $A B C D=B C \times A B=8 \times 4=32 \mathrm{~m}^{2}$

and $\quad$ area of semi-circie $D F E=\frac{\pi r^{2}}{2}=\frac{\pi}{2}(2)^{2}=2 \pi \mathrm{m}^{2}$

$\therefore$ Area of shaded region $=$ Area of rectangle $A B C D+$ Area of semi-circle $D F E$

$=(32+2 \pi) m^{2}$