Question:
Find the area of an equilateral triangle having each side of length 10 cm.
Solution:
Given:
Side of the equilateral triangle = 10 cm
Thus, we have:
Area of the equilateral triangle $=\frac{\sqrt{3}}{4}$ side $^{2}$
$=\frac{\sqrt{3}}{4} \times 10 \times 10$
$=25 \times 1.732$
$=43.3 \mathrm{~cm}^{2}$