Find the area of a trapezium whose parallel sides are of length 16 dm

Given:

Lengths of the parallel sides are $16 \mathrm{dm}$ and $22 \mathrm{dm}$.

And, height between the parallel sides is $12 \mathrm{dm}$.

Area of trapezium $=\frac{1}{2} \times($ Sum of the parallel sides $) \times($ Height $)$

$=\frac{1}{2} \times(16+22) \times(12)$

$=228 \mathrm{dm}^{2}$

$=228 \times \mathrm{dm} \times \mathrm{dm}$

$=228 \times \frac{1}{10} \mathrm{~m} \times \frac{1}{10} \mathrm{~m}$

$=2.28 \mathrm{~m}^{2}$