Question:
Find the area of a trapezium whose parallel sides are 38.7 cm and 22.3 cm, and the distance between them is 16 cm.
Solution:
Area of a trapezium $=\frac{1}{2} \times($ Sum of parallel sides $) \times($ Distance between them $)$
$=\left\{\frac{1}{2} \times(38.7+22.3) \times 16\right\} \mathrm{cm}^{2}$
$=\left(\frac{1}{2} \times 61 \times 16\right) \mathrm{cm}^{2}$
$=(61 \times 8) \mathrm{cm}^{2}$
$=488 \mathrm{~cm}^{2}$
Hence, the area of the trapezium is $488 \mathrm{~cm}^{2}$.