Question:
Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.
Solution:
Radius, $r=6 \mathrm{~cm}$; sector angle, $\theta=60$ degrees
Area of the sector
$=\frac{\theta}{360} \times \pi r^{2}=\frac{60}{360} \times \frac{22}{7} \times(6)^{2} \mathrm{~cm}^{2}$
$=\frac{1}{6} \times \frac{22}{7} \times(6)^{2} \mathrm{~cm}^{2}=\frac{132}{7} \mathrm{~cm}^{2}$