Question:
Find the area of a rectangular park which is $36 \frac{3}{5} \mathrm{~m}$ long and $16 \frac{2}{3} \mathrm{~m}$ broad.
Solution:
Area of the rectangular park $=$ Length of the park $\times$ Breadth of the park ( $\because$ Area of rectangle $=$ Length $\times$ Breadth)
$=36 \frac{3}{5} \times 16 \frac{2}{3}$
$=\left(36+\frac{3}{5}\right) \times\left(16+\frac{2}{3}\right)$
$=\frac{183}{5} \times \frac{50}{3}$
$=\frac{183 \times 50}{5 \times 3}$
$=\frac{9150}{15}$
$=610 \mathrm{~m}^{2}$
Therefore, the area of the rectangular park is $610 \mathrm{~m}^{2}$.