Find the area of a quadrant of a circle whose circumference is 88 cm.

Question:

Find the area of a quadrant of a circle whose circumference is 88 cm.

Solution:

Let the radius of the circle be r.
​Now,

Circumference $=88$

$\Rightarrow 2 \pi r=88$

$\Rightarrow r=14 \mathrm{~cm}$

Now,

Area of quadrant $=\frac{1}{4} \pi r^{2}=\frac{1}{4} \times \frac{22}{7} \times(14)^{2}=154 \mathrm{~cm}^{2}$

Hence, the area of the quadrant of the circle is 154 cm2.

 

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