Find the area of a quadrant of a circle whose circumference is 44 cm.

Let the radius of the circle be r.
​Now,

Circumference $=44$

$\Rightarrow 2 \pi r=44$

$\Rightarrow r=7 \mathrm{~cm}$

Now,

Area of quadrant $=\frac{1}{4} \pi r^{2}=\frac{1}{4} \times \frac{22}{7} \times(7)^{2}=38.5 \mathrm{~cm}^{2}$

Hence, the area of the quadrant of the circle is 38.5 cm2.