Find the area bounded under the curve

$y=3 x^{2}+6 x+7$

Area bounded under the curve within $x=5$ and $x=10$ is calculated by the method of inteqration.

Area $=\int_{x=5}^{x=10} y d x=\int_{5}^{10}\left(3 x^{2}+6 x+7\right) d x=\left[3 \frac{x^{8}}{3}+6 \frac{x^{2}}{2}+7 x\right]_{10_{5}}=1135$ sq. units