Find the additive inverse of:

(i) $\frac{7}{-10}=\frac{7 \times-1}{-10 \times-1}=\frac{-7}{10}$

Additive inverse of $\frac{-7}{10}$ is $\frac{7}{10}$.

(ii) Additive inverse of $\frac{8}{5}$ is $\frac{-8}{5}$.