find out the most stable ion in its reduced form.
EᶱCr2O72-/Cr3+ = 1.33V
EᶱMnO4–/Mn2+ = 1.51V
EᶱCl2/Cl– = 1.36V
EᶱCr3+/Cr = -0.74V
(i) Cl–
(ii) Cr3+
(iii) Cr
(iv) Mn2+
Option (iv) is the answer.
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