Ferrous sulphate heptahydrate is used to fortify foods with iron.

Question:

Ferrous sulphate heptahydrate is used to fortify foods with iron. The amount (in grams) of the salt required to achieve $10 \mathrm{ppm}$ of iron in $100 \mathrm{~kg}$ of wheat is___________ .Atomic weight: $\mathrm{Fe}=55.85 ; \mathrm{S}=32.00 ; \mathrm{O}=16.00$

Solution:

(4.96)

$10=\frac{\text { Mass of Fe }(\text { in } \mathrm{g})}{100 \times 1000} \times 10^{6}$

$\Rightarrow$ Mass of $\mathrm{Fe}=1 \mathrm{~g}$

Molar mass of $\mathrm{FeSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}=278$

$56 \mathrm{~g}$ of iron present in 1 mole of $\mathrm{FeSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}$

$1 \mathrm{~g}$ of Fe present in $\frac{278}{56} \mathrm{~g}$ of salt $=4.96 \mathrm{~g}$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now