Question:
Factorize each of the following expression:
(2a − b)2 − 16c2
Solution:
$(2 a-b)^{2}-16 c^{2}$
$=(2 a-b)^{2}-(4 c)^{2}$
$=[(2 a-b)-4 c][(2 a-b)+4 c]$
$=(2 a-b-4 c)(2 a-b+4 c)$
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