Factorize each of the following expression:

$16(a-b)^{3}-24(a-b)^{2}$

$=8(a-b)^{2}[2(a-b)-3]$            $\left\{\right.$ Taking $\left[8(a-b)^{2}\right]$ as the common factor $\}$

$=8(a-b)^{2}(2 a-2 b-3)$