Factorize each of the following algebraic expression:

To factorise $a^{2}+3 a-88$, we will find two numbers $p$ and $q$ such that $p+q=3$ and $p q=-88$.

Now,

$11+(-8)=3$

And

$11 \times(-8)=-88$

Splitting the middle term $3 \mathrm{a}$ in the given quadratic as $11 \mathrm{a}-8 \mathrm{a}$, we get:

$a^{2}+3 a-88=a^{2}+11 a-8 a-88$

$=\left(a^{2}+11 a\right)-(8 a+88)$

$=a(a+11)-8(a+11)$

$=\left(a^{2}+11 a\right)-(8 a+88)$

$=a(a+11)-8(a+11)$

$=(a-8)(a+11)$