Question:
Factorize:
$64 a^{3}-343$
Solution:
$64 a^{3}-343=(4 a)^{3}-(7)^{3}$
$=(4 a-7)\left(16 a^{2}+4 a \times 7+7^{2}\right)$
$=(4 a-7)\left(16 a^{2}+28 a+49\right)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.