Question:
Factorize:
$7 a^{3}+56 b^{3}$
Solution:
$7 a^{3}+56 b^{3}=7\left(a^{3}+8 b^{3}\right)$
$=7\left[(a)^{3}+(2 b)^{3}\right]$
$=7(a+2 b)\left[a^{2}-a \times 2 b+(2 b)^{2}\right]$
$=7(a+2 b)\left(a^{2}-2 a b+4 b^{2}\right)$
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