Question:
Factorize:
$125 a^{3}+b^{3}+64 c^{3}-60 a b c$
Solution:
$125 a^{3}+b^{3}+64 c^{3}-60 a b c=(5 a)^{3}+(b)^{3}+(4 c)^{3}-3 \times 5 a \times b \times 4 c$
$=(5 a+b+4 c)\left[(5 a)^{2}+(b)^{2}+(4 c)^{2}-5 a \times b-b \times 4 c-5 a \times 4 c\right]$
$=(5 a+b+4 c)\left(25 a^{2}+b^{2}+16 c^{2}-5 a b-4 b c-20 a c\right)$