Factorize:
$27 a^{2}-48 b^{2}$
$27 a^{2}-48 b^{2}=3\left(9 a^{2}-16 b^{2}\right)$
$=3\left[(3 a)^{2}-(4 b)^{2}\right]$
$=3(3 a-4 b)(3 a+4 b)$
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