Factorize:

We have:

$15 x^{2}+2 x-8$

We have to split 2 into two numbers such that their sum is 2 and their product is $(-120)$, i.e., $15 \times(-8)$.

Clearly, $12+(-10)=2$ and $12 \times(-10)=-120$

$\therefore 15 x^{2}+2 x-8=15 x^{2}+12 x-10 x-8$

$=3 x(5 x+4)-2(5 x+4)$

$=(5 x+4)(3 x-2)$