Factorise:

Question:

Factorise:
6x2 − 17x − 3

Solution:

The given expression is $6 x^{2}-17 x-3$.

Find two numbers that follow the conditions given below :

Sum $=-17$

Product $=6 \times-3=-18$

Clearly, the numbers are $-18$ and 1 .

$6 x^{2}-17 x-3=6 x^{2}-18 x+x-3$

$=6 x(x-3)+1(x-3)$

$=(6 x+1)(x-3)$

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