Question: Factorise:
p2 + 6p + 8
Solution:
The given expression is $p^{2}+6 p+8$.
Find two numbers that follow the conditions given below:
Sum $=6$
Product $=8$
Clearly, the numbers are 4 and 2 .
$p^{2}+6 p+8=p^{2}+4 p+2 p+8$
$=p(p+4)+2(p+4)$
$=(p+4)(p+2)$
