Factorise:9y2 − 12y + 4
We have:
$9 y^{2}-12 y+4=(3 y)^{2}-2 \times 3 y \times 2+(2)^{2}$
$=(3 y-2)^{2}$
$\therefore 9 y^{2}-12 y+4=(3 y-2)^{2}$
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