Factorise:

Question:

Factorise:
2a + 6b − 3(a + 3b)2

Solution:

We have:

$2 a+6 b-3(a+3 b)^{2}=2(a+3 b)-3(a+3 b)^{2}$

$=(a+3 b)\{2-3(a+3 b)\}$

$=(a+3 b)(2-3 a-9 b)$

$\therefore 2 a+6 b-3(a+3 b)^{2}=(a+3 b)(2-3 a-9 b)$

 

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now