Factorise:
$3 x^{2}-14 x+8$
$3 x^{2}-14 x+8=3 x^{2}-12 x-2 x+8$
$=3 x(x-4)-2(x-4)$
$=(x-4)(3 x-2)$
Hence, factorisation of $3 x^{2}-14 x+8$ is $(x-4)(3 x-2)$.
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