Question:
Factorise:
p2 − 10p + 25
Solution:
We have:
$p^{2}-10 p+25=p^{2}-2 \times p \times 5+(5)^{2}$
$=(p-5)^{2}$
$\therefore p^{2}-10 p+25=(p-5)^{2}$
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