Factorise:4x2 − 9y2
We have:
$4 x^{2}-9 y^{2}=(2 x)^{2}-(3 y)^{2}$
$=(2 x+3 y)(2 x-3 y)$
$\therefore 4 x^{2}-9 y^{2}=(2 x+3 y)(2 x-3 y)$
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