Factorise:

Question:

Factorise:

$40+3 x-x^{2}$

 

Solution:

$-x^{2}+3 x+40$

$=-x^{2}+8 x-5 x+40$

$=-x(x-8)-5(x-8)$

$=(x-8)(-x-5)$

$=(8-x)(x+5)$

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