Factorise:121a2 − 88ab + 16b2
We have:
$121 a^{2}-88 a b+16 b^{2}=(11 a)^{2}-2 \times 11 a \times 4 b+(4 b)^{2}$
$=(11 a-4 b)^{2}$
$\therefore 121 a^{2}-88 a b+16 b^{2}=(11 a-4 b)^{2}$
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