Factorise:
$6 x^{2}-11 x-35$
$6 x^{2}-11 x-35=6 x^{2}-21 x+10 x-35$
$=3 x(2 x-7)+5(2 x-7)$
$=(2 x-7)(3 x+5)$
Hence, factorisation of $6 x^{2}-11 x-35$ is $(2 x-7)(3 x+5)$.
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