Factorise:4y2 + 20y + 25
We have:
$4 y^{2}+20 y+25=(2 y)^{2}+2 \times 2 y \times 5+(5)^{2}$
$=(2 y+5)^{2}$
$\therefore 4 y^{2}+20 y+25=(2 y+5)^{2}$
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