Factorise:

We have:

$16 x^{5}-144 x^{3}=16 x^{3}\left(x^{2}-9\right)$

$=16 x^{3}\left\{(x)^{2}-(3)^{2}\right\}$

$=16 x^{3}(x+3)(x-3)$

$\therefore 16 x^{5}-144 x^{3}=16 x^{3}(x+3)(x-3)$