Factorise:
$(3 a+5 b)^{2}-4 c^{2}$
$=(3 a+5 b)^{2}-(2 c)^{2}$
$=(3 a+5 b+2 c)(3 a+5 b-2 c) \quad\left[a^{2}-b^{2}=(a+b)(a-b)\right]$
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