Question:
Factorise:
16(2p − 3q)2 − 4(2p − 3q)
Solution:
We have:
$16(2 p-3 q)^{2}-4(2 p-3 q)=(2 p-3 q)\{16(2 p-3 q)-4\}$
$=(2 p-3 q)(32 p-48 q-4)$
$\therefore 16(2 p-3 q)^{2}-4(2 p-3 q)=(2 p-3 q)(32 p-48 q-4)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.