Question:
Factorise:
9a2b2 − 25
Solution:
We have:
$9 a^{2} b^{2}-25=(3 a b)^{2}-(5)^{2}$
$=(3 a b+5)(3 a b-5)$
$\therefore 9 a^{2} b^{2}-25=(3 a b+5)(3 a b-5)$
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