Factorise:x3 − 64x
We have:
$x^{3}-64 x=x\left(x^{2}-64\right)$
$=x\left\{(x)^{2}-(8)^{2}\right\}$
$=x(x+8)(x-8)$
$\therefore x^{3}-64 x=x(x+8)(x-8)$
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