Question:
Factorise:
3m2 + 24m + 36
Solution:
The given expression is $3 m^{2}+24 m+36$.
Find two numbers that follow the conditions given below:
Sum $=24$
Product $=36 \times 3=108$
Clearly, the numbers are 18 and 6 .
$3 m^{2}+24 m+36=3 m^{2}+18 m+6 m+36$
$=3 m(m+6)+6(m+6)$
$=(3 m+6)(m+6)=3(m+2)(m+6)$
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