Question:
Factorise:
63a2 − 112b2
Solution:
We have:
$63 a^{2}-112 b^{2}=7\left(9 a^{2}-16 b^{2}\right)$
$=7\left\{(3 a)^{2}-(4 b)^{2}\right\}$
$=7(3 a+4 b)(3 a-4 b)$
$\therefore 63 a^{2}-112 b^{2}=7(3 a+4 b)(3 a-4 b)$
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