Question: Factorise:
p2 + 6p − 16
Solution:
The given expression is $p^{2}+6 p-16$.
Find two numbers that follow the conditions given below:
Sum $=6$
Product $=-16$
Clearly, the numbers are 8 and $-2$.
$p^{2}+6 p-16=p^{2}+8 p-2 p-16$
$=p(p+8)-2(p+8)$
$=(p+8)(p-2)$
