Question:
Factorise:
3(a − 2b)2 − 5(a − 2b)
Solution:
$3(a-2 b)^{2}-5(a-2 b)=(a-2 b)\{3(a-2 b)-5\}$
$=(a-2 b)(3 a-6 b-5)$
$\therefore 3(a-2 b)^{2}-5(a-2 b)=(a-2 b)(3 a-6 b-5)$
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