Question:
Factorise:
a2b2 − 6abc + 9c2
Solution:
We have:
$a^{2} b^{2}-6 a b c+9 c^{2}=(a b)^{2}-2 \times a b \times 3 c+(3 c)^{2}$
$=(a b-3 c)^{2}$
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