Question:
Examine the consistency of the system of equations
$x+2 y=2$
$2 x+3 y=3$
Solution:
The given system of equations is:
$x+2 y=2$
$2 x+3 y=3$
The given system of equations can be written in the form of AX = B, where
$A=\left[\begin{array}{ll}1 & 2 \\ 2 & 3\end{array}\right], X=\left[\begin{array}{l}x \\ y\end{array}\right]$ and $B=\left[\begin{array}{l}2 \\ 3\end{array}\right]$
Now,
$|A|=1(3)-2(2)=3-4=-1 \neq 0$
$\therefore A$ is non-singular.
Therefore, $A^{-1}$ exists.
Hence, the given system of equations is consistent.