Evaluate:

To find: the value of ${ }^{62} \mathrm{P}_{3}$

Formula Used:

Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,

${ }_{n} P_{r}=\frac{n !}{(n-r) !}$

Therefore,

${ }_{62} \mathrm{P}_{3}=\frac{62 !}{(62-3) !}$

${ }^{62} \mathrm{P}_{3}=62 \times 61 \times 60 \times 59=226920$

Thus, the value of ${ }^{62} \mathrm{P}_{3}$ is 226920 .