Question:
Evaluate:
${ }^{62} P_{3}$
Solution:
To find: the value of ${ }^{62} \mathrm{P}_{3}$
Formula Used:
Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,
${ }_{n} P_{r}=\frac{n !}{(n-r) !}$
Therefore,
${ }_{62} \mathrm{P}_{3}=\frac{62 !}{(62-3) !}$
${ }^{62} \mathrm{P}_{3}=62 \times 61 \times 60 \times 59=226920$
Thus, the value of ${ }^{62} \mathrm{P}_{3}$ is 226920 .
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