Question:
Evaluate:
$\sqrt[3]{\frac{-27}{125}}$
Solution:
$\sqrt[3]{\frac{-27}{125}}$
By factorisation:
$\sqrt[3]{\frac{27}{125}}=\sqrt[3]{\frac{3 \times 3 \times 3}{5 \times 5 \times 5}}$
$\therefore \sqrt[3]{\frac{-27}{125}}=\frac{-3}{5}$
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