Question:
Evaluate:
(i) (1.2)3
(ii) (3.5)3
(iii) (0.8)3
(iv) (0.05)3
Solution:
(i) $(1.2)^{3}=(1.2 \times 1.2 \times 1.2)=1.728$
Thus, the cube of $1.2$ is $1.728$.
(ii) $(3.5)^{3}=(3.5 \times 3.5 \times 3.5)=42.875$
Thus, the cube of $3.5$ is $42.875$.
(iii) $(0.8)^{3}=(0.8 \times 0.8 \times 0.8)=0.512$
Thus, the cube of $0.8$ is $0.512$.
(iv) $(0.05)^{3}=(0.05 \times 0.05 \times 0.05)=0.000125$
Thus, the cube of $0.05$ is $0.000125$.